... PERFECT TOGETHER!!
ANSWER KEY FOR PS 8B (Ignore the fact that it's titled "PS 10C"... that's an "old" number)
Chapter 8 Review & Chapter Test
#1 - Infinity
excluding section 8-8 Factoring by Grouping (which is really not too much different than the beautiful symmetry and proportion inherent in the Area Model).
I'll be on pretty late.. So hopefully you answer my questions when they come!
ReplyDeleteI'll be checking in early (4-5pm-ish) and late (10pm-ish). I can't imagine there will be any questions... you guys are all rock-solid... I am expecting all 100's on the test!
ReplyDeleteGOOD NEWS!!!! We will have the test even if there is a delayed opening!!
What are the prime factors in the review packet?
ReplyDeleteSorry , my bad. Prime expressions
ReplyDeleteYou mean prime polynomials!!
ReplyDeleteYou tell me, then I'll tell you!!!
(No need for last names, btw!)
prime polynomial. #10, 14, 15 and 18
ReplyDeleteI also just checked the answer key and for #24 i got (4x^2-9y^2) (4x^2+9y^2)
ReplyDeleteYou factored... but you didn't FULLY FACTOR... can you see why??
ReplyDeleteI see. 4 and 9 are perfect squares
ReplyDeleteYUP!
ReplyDeleteI'll be back later... I expect to see TEAM ALGEBRA helping each other with questions and answers!!!
If you factor something out, like for example if the problem was 3c(15c^4-21c^2+9), if I were to factor out another 3 would I add it to the 3c or multiply it by 3?
ReplyDeleteI think it's multiply..
I don't really understand #28 on pg 524. Would it be 30?
ReplyDeleteANY ALGEBUDDY WANNA HELP ME?!
ReplyDelete=P
You can only factor a number out of 2 binomials if it can be pulled out of every monomial, right? So like for example you can't factor n out of this problem (3m+11n)(2m+n)?
ReplyDeleteFor #71 on pg 526, do you simplify the expression then divide it by 4 to get the length of 1 side?
ReplyDeleteI don't know what to do for #75.. Or should I not do that because it is in "factoring by grouping"? But it said factor completely, so..?
ReplyDeleteWill there be factoring 4 term polynomials on the test?
ReplyDeleteFor #23 on the Chapter Test, I'm having a hard time figuring out what to put on the outside of the area model! I'm getting stuck with all the negatives! For the top left & lower right boxes I have -2n & -3n.. And there is no way I can place the negatives to agree with the other boxes, too!
ReplyDeleteHow do you figure out #25?
ReplyDeleteI'm still here... And waiting for 10:00 to come =)
ReplyDeleteFirst, you are not responsible for section 8-8 "Factoring by Grouping" - so breathe a sigh of relief!!
ReplyDelete*Breathes a sigh of relief*
ReplyDeleteOkay!
So no 4-term polynomial solving?
ReplyDelete#28 on 524 is 30, nicely done!
ReplyDeleteFor 526 #71... THINK THINK THINK!!!
If a square has an area of 9n^2+54n+81... the only way you can find a "clean" length of a side is if this quadratic polynomial is a perfect square trinomial... so your ONLY HOPE for the first term is 3n and your ONLY HOPE for the last term is 9. Lucky for you,
(3x+9)^2=9n^2+54n+81
... so you're a FACTORING FOOL!!
No 4-term polynomial factoring on this test... sorry!!
ReplyDeleteOoooh! So it's a perfect square! In those problems, is the only method a little guess 'n' check?
ReplyDeleteIt's okay!! Trust Me!! =)
ReplyDeleteThe ChapTest #25 is the SAME ISSUE as #71... can you work it out now?
ReplyDeleteNote: Somebody above got area & perimeter mixed up! Mr. or Ms. "divide by 4" at 8:01 pm
What is guess and check about a perfect square... it either is or isn't. You could have put that one in an AREA MODEL, too. Remember, the AREA MODEL works for all quadratics... remember that GCF!!
ReplyDeleteOh that was me.. (;
ReplyDeleteI'll try to figure it out!
Is #25 (9p+5)^2??
ReplyDeleteAnd oh yeah! Got it!
ChapTest #21,22,24 are not in play... forget 'em.
ReplyDeleteChapTest #23; factor out the 3n^2 and it should be a fairly-easy-schmeezy area model, right?
OHHH right! For #23! I did the wrong factors..
ReplyDeleteWhy are you asking me? How can you figure out if (9p+5)^2 is the right answer.
ReplyDeletePretend I gave you the problem:
Simplify (9p+5)^2... what would you do??
You would multiply (9p+5)(9p+5) and get 81p^2+90p+25... that's what you would do, right??
So, did you get the right answer?? Multiply it back and check it yourself (aka dig the ditch and fill it back in!)
Is the answer to #23 (n+3)(2n-1)??
ReplyDeleteI filled it back in! And I'm thinking YEP!
ReplyDeleteThanks for the help! I'll try to do some of Problem Set 8B in the morning =) Good night!
ReplyDelete#23... you factored out the 3n^2 but you forgot to include it in your fully factored answer... I told you that you would get that wrong on the test!!
ReplyDeleteBUT... I Didn't get it wrong! =D
ReplyDelete