UNIT TEST on Sections 9-1 thru 9-6 ONLY
ON FRIDAY!! YIPPEE!!
Better Way - by Ben Harper
hw #9-6
READ pg 567-571
Complete Problem Set 9A (see answers on MathChamber)
pg 571-573 #7,11,15
for #23-28, DO NOT SOLVE, just choose a method and supply your reasoning;
#41
A SMART STUDENT would begin to look at pages 590-91... the test (ON FRIDAY!!) will be on sections 9-1 thru 9-6 ONLY... we're done!!
Chapter Test on pg 593; OMIT/IGNORE questions #20-22
You will need to solve a quadratic using EACH method (#2-5 on PS 9A) on the test...
ReplyDeleteI'm kind of confused on #41... not sure where to begin. Please help!
ReplyDeleteFor number 41, I have the equation, but i dont know what the discriminant would be.
ReplyDeleteDoes the test have to be on Friday? PLEASE? I have the WordMasters National Analogies test on Friday! PLEASE!
ReplyDeleteWhat would a reason for using the quadratic formula be?
ReplyDeleteAnd for using the "complete the square" method?
I can't figure out #6 on the Problem Set.. I checked the answers sheet but it still doesn't make sense to me how you can factor it..
ReplyDeleteI don't really get # 41 or the descriminant. Can you help?
ReplyDeleteAaron
I'm still having difficulty with... graphing..
ReplyDeleteOn the test, will the only way to solve quadratics by graphing be a table of values?
For #15, in the Quadratic formula, do we subsitute zero in for c or just leave it out?
ReplyDeleteCan you complete the square on quadratics when the coefficent of x^2 is more than 1?
ReplyDeleteI don't know where to start on #41!
ReplyDeleteYou should be able to reason your way through the reasons to use the various methods to solve (solve means to obtain the x-intercepts, aka zeroes, aka roots, aka solutions) a quadratic equation.
ReplyDeleteSquare rooting works when there is a zero 'b' coefficient or "no middle term"
Factoring works when you can factor (duh!)... you don't know until you try, so what some people (I call them weenies) do is complete the square or use the QF when factoring seems difficult.
Complete the Square can be used for any quadratic equation. "Real students" of Mr. Chamberlain look forward to completing the square. Some students (half weenies) will opt to use the QF when there is an 'a' coefficient not = 1 OR a 'b' coefficient that is not an even integer. It's a judgment call for the solver.
QF solves all. It's a formula that get the input of 'a','b', and 'c' from the standard form of a quadratic (when set equal to zero, of course).
When completing the square on equations with an 'a' coefficient <> 1, your first step is to SIMPLY divide everything by 'a'... take a look at our proof of the QF or a PH Video Tutor.
ReplyDeleteThe discriminant is simply b^2 - 4ac, (sing with me now) just plug-it-in plug-it-in and figure it out.
ReplyDeleteDo we use a table of values for #9 C in the problem set or should we use a different method? Is there even a different method for solving that equation?
ReplyDeleteAnd I'm still confused on velocity..
ReplyDeleteX EQUALS NEGATIVE B, PLUS OR MINUS THE SQUARE ROOT OF B SQUARED MINUS 4 AC, ALL OVER 2 A!
ReplyDeleteMy answers for #10 in the Problem Set weren't the same! Is that wrong?
ReplyDeleteFor Complete the Square on #10, I got
ReplyDeletex={2,4}
For the Quadratic Formula, I got
x={1.27,4.73}
Velocity is distance/time (read "distance over time) where distance can be expressed in positive or negative terms. Velocity is typically used to measure distance/time in vertical motion problems, where "skyward" (up) velocity is positive and "ground-bound" (down) velocity is negative.
ReplyDeleteSpeed is the absolute value of velocity.
If #41 is your only problem, we'll discuss it in class.
ReplyDeletePS 9A #6 can be factored my darlings, go back to last unit, do not pass GO, do not collect $200.
ReplyDeleteDear #10, if you get two different answers, YOU GOOFED! The QF is simply a matter of evaluating an expression whilst substituting values (IN PARENTHESES!!!) for variables. Go back to September, do not pass GO, do not collect $200.
ReplyDeleteThe answers to PS 9A are on the Unit 9 page on MathChamber (for those who ever go there?!).
ReplyDeleteDear #15,
ReplyDeleteQ. If you don't c a 'c' term (get it, lol), then what could you substitute for it??
A. ZERO!!! If you don't c 'c' - c=0.
c?
I c!
ReplyDeleteAnd the answers only go up to #8!
When graphing, always find the vertex first. This is accomplished by finding the axis of symmetry (x=-b/2a, yes?) and then using that 'x' value to find the corresponding 'y' value.
ReplyDeleteThe 'c' value gives you the y-intercept, yes?
Since a parabola is symmetric about its axis, you can reflect the y-intercept to find a third point, yes?
Does that make graphing a bit easier??
Based on the given formula, you should be able to setup AND SOLVE an equation for PS #9. We'll review that one in class, if necessary.
ReplyDeleteCan I use a table of values to solve #9 or is there a better way?
ReplyDeleteI would like to review it in class!
ReplyDeleteOh, for #10 I just messed up on multiplying.. 8*4 is not 24!
ReplyDeleteCould you come on Alge-Chat??
ReplyDeletegimme a few minutes (8:50) for a chat
ReplyDeleteOkey dokey!
ReplyDeleteim still having trouble with #36 on the chapter review
ReplyDeletesee the next hw post
ReplyDelete