This Blog exists for the collective benefit of all algebra students. While the posts are specific to Mr. Chamberlain's class, any and all "algebra-ticians" are welcome. The more specific your question (including your own attempts to answer it) the better.
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Wednesday, January 5, 2011
hw #5-4 Get Ready for the QUIZ!
hw #5-4
a) Problem Set 5B
b) pg 323-325 #3-42 mult of 3
EC point slope: is useful when you know the the slope and one point (trying to figure out where the other points go) and for when you know two points (trying to figure out the slope slope intercept: is best used when you know the slope and the y intercept and only one point. y=mx+b where m is the slope and b is the y intercept. standard: this technique is most useful when you are going to graph. in the formula Ax+Bx=C you simply cover up one part (Ax or Bx) and divide both sides by the coefficient. You then graph the two points and extend the lines if necesary.
#39)- Standard form is the best to use when you are talking about situations like the one we solved in class where coefficients represent rates of the variables x and y and the two terms together is a given value C. It's usually used when making some graphs where there aren't obvious ind. and dep. variables to show how many of 1 you need when the other is at a certain value. Slope-intercept form is best when you're dealing with making graphs and the coordinate plane as the slope and y-intercept are important and visually seen. It helps you create lines a lot easier than trying to do it from the other forms. Last, point-slope form is best when you are given specific information on the points of a line or the slope, but not the y-intercept, graph, etc. It lets you substitute the values of x and y for a point and find other points on the line or even get the slope based of the slope formula. This form is usually used to locate other points on a line too far to find on a graph or solve for other missing variables.
#42)- When you solve the equation for y, you end up with the equation: y=C/B-Ax/B or y=-Ax/B+C/B. If there had been variables there, A would be slope and C would be the y-intercept. So, with the equation y=-A(or m)x/B+C(or b)/B, I got that for Ax+By=C....
39) STANDARD FORM- Standard form is most useful when doing problem such as where you are adding 2 similar things to each other to equal a total (c), the 2 similarities going along each axis. It is best as a visual for linear equations & graphing linear equations. SLOPE-INTERCEPT FORM- Slope-Intercept form is most useful when you know the features slope & the y intercept, making it easier to plug in the numbers in the equation. (Not that we don't want to be miserable) Slope-intercept form is also useful when graphing; the slope & the y-intercept can be read directly off of the equation and used to graph. POINT-SLOPE FORM- Point-slope form is most useful when the information given to you are the coordinates, ex. (x,y) and the slope. Using this formula, you can figure out an equation which can be used for graphing. Point-slope form is best for converting a pair of coordinates & slope into y=mx+b form of slope-intercept.
42)Coming Soon.. Still trying to figure that out :)
As for Ryan's question, Im not sure exactly what you mean. You will add (or subtract) the y1 (constant) term to BOTH sides. Since you probably already distributed on the "right side" you'll have the mx term and a constant term in place. Since the y1 term is a constant, it should be combined with the constant and NOT the mx term. Did I understand/answer your question?
For #5 in problem set 5B, it would probably be helpful to draw the graph. The slope value will depend on the unit of measure you use for the independent variable, time. You have a choice of minutes or hours.
It should be pretty clear that the y-intercept is at (0,12). From your graph, you should be able to quantify the slope.
If you used minutes, you should have calculated a slope of -4/30 or (reduced) -2/15.
If you used minutes, you should have calculated a slope of -4/.5 or (simplified) -8.
At this point you gotsk a slope and a y-intercept, therefore voila:
42) I solved the equation for y to figure out what the slope-intercept form of that equation would be. First I would subtract Ax from both sides, then divide both sides by B to isolate x. The slope then would be -Ax/B and the y-intercept would be C/B, according to the form of slope-intercept form of y=mx+b.
EC
ReplyDeletepoint slope:
is useful when you know the the slope and one point (trying to figure out where the other points go) and for when you know two points (trying to figure out the slope
slope intercept:
is best used when you know the slope and the y intercept and only one point. y=mx+b where m is the slope and b is the y intercept.
standard:
this technique is most useful when you are going to graph. in the formula Ax+Bx=C you simply cover up one part (Ax or Bx) and divide both sides by the coefficient. You then graph the two points and extend the lines if necesary.
EC
ReplyDeletefor number 42 the y intercept is (0,c/b) nad the slope is -c/b over c/a
did i get it right???
ReplyDeleteHaving trouble finding an equation for #5 problem set 5B
ReplyDeleteExtra Credit.....
ReplyDelete#39)- Standard form is the best to use when you are talking about situations like the one we solved in class where coefficients represent rates of the variables x and y and the two terms together is a given value C. It's usually used when making some graphs where there aren't obvious ind. and dep. variables to show how many of 1 you need when the other is at a certain value.
Slope-intercept form is best when you're dealing with making graphs and the coordinate plane as the slope and y-intercept are important and visually seen. It helps you create lines a lot easier than trying to do it from the other forms.
Last, point-slope form is best when you are given specific information on the points of a line or the slope, but not the y-intercept, graph, etc. It lets you substitute the values of x and y for a point and find other points on the line or even get the slope based of the slope formula. This form is usually used to locate other points on a line too far to find on a graph or solve for other missing variables.
#42)- When you solve the equation for y, you end up with the equation: y=C/B-Ax/B or y=-Ax/B+C/B. If there had been variables there, A would be slope and C would be the y-intercept. So, with the equation y=-A(or m)x/B+C(or b)/B, I got that for Ax+By=C....
Slope= -A/B and that Y-Intercept=C/B.
For #11 in problem set 5B, how would you figure out the slope intercept?
ReplyDeleteOn Problem Set 5B, when you do the second step of converting point-slope to slope-intercept (adding y1 to both sides), do you add it to the mx term?
ReplyDelete39)
ReplyDeleteSTANDARD FORM- Standard form is most useful when doing problem such as where you are adding 2 similar things to each other to equal a total (c), the 2 similarities going along each axis. It is best as a visual for linear equations & graphing linear equations.
SLOPE-INTERCEPT FORM- Slope-Intercept form is most useful when you know the features slope & the y intercept, making it easier to plug in the numbers in the equation. (Not that we don't want to be miserable) Slope-intercept form is also useful when graphing; the slope & the y-intercept can be read directly off of the equation and used to graph.
POINT-SLOPE FORM- Point-slope form is most useful when the information given to you are the coordinates, ex. (x,y) and the slope. Using this formula, you can figure out an equation which can be used for graphing. Point-slope form is best for converting a pair of coordinates & slope into y=mx+b form of slope-intercept.
42)Coming Soon..
Still trying to figure that out :)
Sorry I'm late guys... I was at a math party, and you know how crazy-exponentially-out-of-control those events can get! Whew! I'm danced out!
ReplyDeleteAs for Ryan's question, Im not sure exactly what you mean. You will add (or subtract) the y1 (constant) term to BOTH sides. Since you probably already distributed on the "right side" you'll have the mx term and a constant term in place. Since the y1 term is a constant, it should be combined with the constant and NOT the mx term. Did I understand/answer your question?
ReplyDeleteFor #11, yuppers (I picked that word up at the math party) that's a batch of work (that's batch with an "a" guys).
ReplyDeleteQ. What can you do with two points?
A. Find the slope!
Q. What can you do with the slope and a point?
A. Write an equation in point-slope form!
Q. What can you do with point-slope form
A. Write an equation in slope-intercept form!
Q. What can you do with an equation in slope-intercept form?
A. Identify the y-intercept!
No wonder I'm so much FUN at parties!!
Let me know if this helped.
For #5 in problem set 5B, it would probably be helpful to draw the graph. The slope value will depend on the unit of measure you use for the independent variable, time. You have a choice of minutes or hours.
ReplyDeleteIt should be pretty clear that the y-intercept is at (0,12). From your graph, you should be able to quantify the slope.
If you used minutes, you should have calculated a slope of -4/30 or (reduced) -2/15.
If you used minutes, you should have calculated a slope of -4/.5 or (simplified) -8.
At this point you gotsk a slope and a y-intercept, therefore voila:
h = (-2/15)t + 12
or
h = -8t + 12
Ca-peesh??
No more math parties for me... I'm gettin' too old!
ReplyDelete42) I solved the equation for y to figure out what the slope-intercept form of that equation would be. First I would subtract Ax from both sides, then divide both sides by B to isolate x. The slope then would be -Ax/B and the y-intercept would be C/B, according to the form of slope-intercept form of y=mx+b.
ReplyDelete*Crossing my fingers that it's correct :)
Yes you answered it Mr. C thanks.
ReplyDelete