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Thursday, May 5, 2011

hw #10-1 & 10-2 Pythagorus was a RADICAL!

CUMULATIVE REVIEW QUESTIONS ARE ALWAYS WELCOME! 

MATHCHAMBER UNIT 10 IS UP & RUNNING AND READY & ABLE TO ASSIST YOUR LEARNING... WHY DON'T YOU PULL UP A CHAIR AND WATCH A FEW VIDEO TUTORS?!

hw #10-1
Read Section 10-1
(Calculator OK)
#6-7, 9,10, 21,29,37

hw #10-2
Read Section 10-2
#1-6, 11-27 Odd
Use the calculator sparingly!

ASK QUESTIONS!  BE READY FOR MONDAY!!

32 comments:

  1. My questions will come.. soon.. :P

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  2. Whats on Monday?

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  3. How do we use algebra to figure out #21? All I can think of is subtracting .5 from 1.3..

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  4. Does the simplified form of a Radical always have a Radical sign in it?

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  5. I'm stuck on #2.. I'm left with √16b^4 * √b
    What should I do?

    By the way.. Do you like my √ symbols?? :D

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  6. I'm really stuck on simplifying with variables inside the radical..

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  7. Oh wait.. I just figured out what to do on #2.. Would 4b^2√b be right?

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  8. I don't know how to start #4.. On pg 610.

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  9. Happy Mother's Day, Everyone!!

    btw, I mis-stated (!!!!) the radical notation on Thursday... the sqrt symbol is called the radical and the expression within the radical is called the radicand. Combined, they for a radical expression, or a radical term of a radical expression.

    Monday is another exciting day of Algebra class. Be ready with your understanding of simplest radical form cuz we're movin' upward and onward!

    Here are some expressions in simplest radical form (love the radical "√" symbol.. thanks):
    a) 5
    b) √7
    c) 5 + √7 (a "mixture")
    gotsk it?

    For 603#21 you have to picture the jogger running along the legs of a rt triangle. The 1.3 miles from start to finish is being measured along the hypotenuse of this triangle. So what was the total mileage along the legs, get it?

    For 610#2, you gotsk it!

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  10. For variables inside the radical, see problem 2 on page 607.

    Let's take a fairly simple example, say you want to simplify √x^3.

    Well, it's not a perfect square (x^2 and x^4 are perfect squares, right?).

    So you can re-write as √(x^2 * x)
    which can be re-written as: √(x^2) * √(x)
    which simplifies to: x√(x)...yes?

    You have to recall your properties of exponents (i.e. x^3 is the sqrt of x^6) and combine them with your new knowledge of the properties of radicals... exciting stuff, eh??

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  11. For 610#4, the first step is to use the division prop of radicals and make it

    √(15x) / √(x^3)

    Hint: In a future step, you will need to use [√(x)/√(x)] as a BIG FAT ONE in order to RATIONALIZE THE DENOMINATOR.

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  12. For help with variables under the radical, watch:

    http://www.phschool.com/atschool/academy123/english/academy123_content/wl-book-demo/ph-304s.html

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  13. is 5 (square root) 2x^3 simplified?
    also where is the square root sign that everybody is using on the keyboard?

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  14. I still don't understand #4 or #5. The fraction confuses me, I don't know what to do.

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  15. Same with #6.. ^^

    And on #17, when I divide 50t^2 up into factors, would I put √25t^2 * √2 or √25 * √2t^2???

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  16. I am completely stuck on section 10-2!!!! :( I have no idea where to start!!! :( :( Can you go over it again on Monday???? :9

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  17. I don't know what to do for #4, #5 or #6 because I watched the video on rationalizing the denominator but here you need to rationalize both the numerator and the denominator!

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  18. For #6 I rationalized the numerator by multiplying it by √6, but now I have 6/√8n and I don't know what to do!

    I think I might know what to do for #5..

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  19. I AGREE WITH ANONYMOUS THAT IS ALSO STUCK ON 10-2!

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  20. I do not like the use of the term "completely stuck"... that is not acceptable.

    To deal with fractions under radicals, you need to understand two topics...

    1) the division property of radicals (should be in your notes with examples
    2) rationalizing the denominator (likewise)

    Both of these topics are also detailed very well in your text book. You are accelerated honors math students... you should have some idea of where to start. Please take a deep breath and re-read problems 5&6 on page 609.

    The essence of simplifying radicals, is to find SOMETHING (i.e. a FACTOR) under the radical that is "square-rootable"... if you can do that, then you are on your way. Do your reading and ask a specific question.

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  21. For #5 I'm stuck with √15/9. AHHHH!!

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  22. WHY ARE YOU RATIONALIZING THE NUMERATOR???????

    Radicals are allowed in the numerator, just not the denominator!!

    (btw, 6 * √(2n) is equal to 6√(2n), not √(8n)... but that was the wrong route anyway)

    Why wouldn't you multiply using the BIG FAT ONE of [√(2n)/√(2n)].

    That will give you √(6)*√(2n) in the numerator, and a nice full 2n in the denominator. NOW, you're still not done. PAY ATTENTION!

    The numerator can be re-combined into √(12n)... do you see a perfect square factor? I do.

    So now you have 2√(3n)/2n, which can be simplified to √(3n)/n.

    Too easy, eh?

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  23. You are not rationalizing BOTH the numerator and denominator, you are rationalizing the denominator... the numerator is just going along for the ride.

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  24. Sorry I didn't post earlier but I don't get #21 on page 63. I understand the runner is on the hypotenuse but i can't come up with any answers.

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  25. 610#5, you're kinda close

    What's √(3) * √(3)?? √(9), right?

    √(9) = 3, right?

    See, you're smarter than you think!

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  26. Dear PW,

    a^2 + b^2 = c^2

    You should be able to identify the legs and hypotenuse... so,

    (.5)^2 + b^2 = (1.3)^2

    Isolate b (ultimately, it's just a square-rootable, yes?

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  27. Is 21n√2n^2 in simplest radical form?

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  28. Ok I accidentally made a=1.3 and c= .5. that explains alot...

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  29. Is 21n√2n^2 in simplest radical form?

    Look underneath the radical... can you find a perfect square factor? Is 2 a perfect square? No, it is not. Is n^2 a perfect square? OMG, yes it is!!

    Simplest form: 21n^2√2, yes?

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  30. if anybody wants to chat, visit alge-chat (visit mathchamber algebra and click on the red "virtual chat" link... i'll be there for a little while...

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  31. Okay I'm coming!!

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  32. On #2, I don't understand how I would get the answer 4b^2√b from √16^b5...

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