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Monday, May 9, 2011

hw #10-3 Radicals are RADICAL!!

Check out the Pearson and Khan Academy Videos on MathChamber

hw#10-3: Due Wed May 11
pg 610-11 #35, 39, 41, 47, 49, 55c
pg 616-17 #1-8, 11, 15, 19, 23, 25, 29, 31, 35, 47, 49
 
A forward thinking algebra student might be looking at the Mid-Chapter Quiz on pg 619

btw... You GOTSK a quiz on Friday on 10-1 thru 10-4 !!
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37 comments:

  1. JulianMay 9, 2011 at 7:25 PM

    I'm confused on where to start with #35 on page 610. Please help!

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  2. JulianMay 9, 2011 at 7:33 PM

    Also, I am confused on #49 page 611.

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  3. Mr. ChamberlainMay 9, 2011 at 7:34 PM

    Draw the picture, Pythagorus! The opposite corners of the park form the endpoints of a hypotenuse of a right triangle, for which the problem gives you information... does that help??

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  4. JulianMay 9, 2011 at 7:36 PM

    Yup thanks.

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  5. JulianMay 9, 2011 at 7:41 PM

    On 55c I somehow ended up with the square root of 1/a over the square root of 2. I don't know what I did wrong. I just know I got the wrong answer.

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  6. Mr. ChamberlainMay 9, 2011 at 8:22 PM

    Gosh, that's a lot of work... how are you doing on all of the other problems??

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  7. Mr. ChamberlainMay 9, 2011 at 8:28 PM

    611#49? You gotsk to draw a picture!!

    Go back to your "It's Hip to be Square" handout.

    If the area of a SQUARE is 24in^2, what must the length of a side be????????

    Are you OK with #35?

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  8. AnonymousMay 9, 2011 at 8:51 PM

    for q 41 in 10-3 the back of the book has the wrong answer it has to be positive

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  9. Mr. ChamberlainMay 9, 2011 at 9:06 PM

    pg617#41... VERY GOOD!!!... you are correct the answer is positive... can you give me the answer in simplest radical form??

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  10. AnonymousMay 10, 2011 at 5:07 PM

    For #35 I have this so far: 26w^2=c^2, and I don't know what to do. The book says the correct answer is w√25. How do I get to this?

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  11. AnonymousMay 10, 2011 at 5:13 PM

    For #41 on pg 610, I got 77√a/2. The book says it should be 77a/2..

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  12. AnonymousMay 10, 2011 at 5:27 PM

    For the second bullet on #49, what properties of radicals are there? What is the one where you divide it up into square factors?

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  13. AnonymousMay 10, 2011 at 5:31 PM

    WHY NEGATIVE EXPONENTS?! WHYYYYYY?!

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  14. AnonymousMay 10, 2011 at 5:55 PM

    for 55c i keep getting the (square root of 2a) over a

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  15. AnonymousMay 10, 2011 at 6:11 PM

    I have no idea how to d #55..
    D:

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  16. AnonymousMay 10, 2011 at 6:12 PM

    If you treat a radicand like a variable, would 4(radical)3 + (radical)3= 5(Radical)3?

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  17. AnonymousMay 10, 2011 at 6:17 PM

    im having trouble with #5

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  18. AnonymousMay 10, 2011 at 6:19 PM

    Nevermind about #55.. I can DO IT! ;D

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  19. AnonymousMay 10, 2011 at 6:23 PM

    Wait never mind. I'm stuck with √10a/a√5

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  20. AnonymousMay 10, 2011 at 6:30 PM

    How would I do √5^2?
    Would there be 2 answers to #4? Because √5^2 could be equal to -5 OR 5.. Right?

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  21. AnonymousMay 10, 2011 at 6:34 PM

    I don't know what to do with #5, it seems like it is already simplified.

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  22. AnonymousMay 10, 2011 at 6:48 PM

    Same for #6..^

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  23. AnonymousMay 10, 2011 at 6:54 PM

    nevermind with about 5 i figured it out

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  24. AnonymousMay 10, 2011 at 6:54 PM

    I don't know how to simplify #8.. So I don't know if it's correct or not..

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  25. LottaMay 10, 2011 at 6:57 PM

    For all of the really simple problems are hard to simplify! I can't find any way!

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  26. AnonymousMay 10, 2011 at 7:03 PM

    By the way.. The person who figured out #5 is not me.. I STILL NEED HELP!

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  27. AnonymousMay 10, 2011 at 7:19 PM

    I don't know what to do for #19.. I ended up with 9.5√5

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  28. AnonymousMay 10, 2011 at 7:39 PM

    I need so much help.. I got 38 for #29.. :(

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  29. AnonymousMay 10, 2011 at 7:41 PM

    I don't know how to simplify #31..

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  30. AnonymousMay 10, 2011 at 8:02 PM

    Nevermind, I did the conjugate thing with #31!

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  31. Mr. ChamberlainMay 10, 2011 at 8:12 PM

    In #29, you are SQUARING a binlmial, you will end up with "middle terms" i.e. the middle terms WILL NOT ADD OUT (aka cancel) to ZERO!

    The middle terms "cancel" only when you have the product of a sum and a difference, e.g.

    (x+y)(x-y)

    Ca-peeesh??

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  32. Mr. ChamberlainMay 10, 2011 at 8:15 PM

    Surprise!!!

    9.5√(5) is equivalent to [19√(5)]/2 !!

    19/2=9.5, yes?

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  33. Mr. ChamberlainMay 10, 2011 at 8:17 PM

    The only error the student made in #8 was to multiply √3 * √3 and get 9 (instead of 3).

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  34. AnonymousMay 10, 2011 at 8:18 PM

    Ohh Okay..
    And For #29, I still don't understand.. Here are my steps:
    Square 5= 25.
    Square √2=2.
    Square -2= 4.
    Square √3= 3.
    Multiply 25 and 2 together and 4 and 3 together. Subtract from eachother..
    50-12=38
    ???

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  35. Mr. ChamberlainMay 10, 2011 at 8:18 PM

    We'll do 55c in class... it is SO MUCH FUN!!!

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  36. AnonymousMay 10, 2011 at 8:23 PM

    Let me see how I should respond to this... YAY!!!!!!!!!!!
    And can we go on Alge-chat?

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  37. AnonymousMay 10, 2011 at 8:45 PM

    I have to go to bed.. I'll look at this tomorrow morning!

    ReplyDelete

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