Total Pageviews

Wednesday, December 1, 2010

hw #4-4 Are you ready for the QUIZ?!

hw #4-4
pg 252  #1-11
pg 282-283 #6-12 EVEN
pg 257 #9-14 ALL

Quiz is on section 4-1 thru 4-3

21 comments:

  1. im stuck on #11 on page 252. I can't think of any real world scenario

    ReplyDelete
  2. ah, finally a question!!! Well, for me, i love the stock market so i decided to do one with that. I know that when the gold stock goes up, along with the major components of the market, the dollar value goes down. So, pretend that X is gold and Y is the dollar and some of the market. When X goes up, Y goes down.

    ReplyDelete
  3. Tyler is correct!

    A less financial example might be as the temperature goes up (ceteris paribus i.e. all things equal) the demand for heating oil goes down.

    ReplyDelete
  4. I have another example. As you eat dinner the amount of food you eat goes up and the amount of food left on your plate goes down.

    ReplyDelete
  5. All the examples are awesome (especially mine!!!!)

    ReplyDelete
  6. Can I use the function graphing paper you handed out in class for #s 9-14

    ReplyDelete
  7. Tyler... always so humble!

    Bailey - yup, that's what it was for... you can graph two equations per coordinate plane... just to save space.

    You can use that paper for problems #9-1,444. You'll see as we move through the course that there will be other (easier!) ways to graphs functions/equations in the coordinate plane... NOTHING BUT FUN!!

    ReplyDelete
  8. Im having trouble with finding equations like on #5

    ReplyDelete
  9. I'm having trouble making a graph for #3 on pg 252

    ReplyDelete
  10. @Anonymous for #5:
    How many biscuits would it have if there were 0 tricks? Do you see a pattern that is decreasing in the amount of biscuits left?
    Hopefully that will start you off :)

    ReplyDelete
  11. Yeah #3 on pg 252 was hard. I sort of did a backwards staircase. I'm not sure if thats right though.

    ReplyDelete
  12. I forgot to write my last name in the last post. Sorry!

    ReplyDelete
  13. Thanks for the help Paul, but I still really don't understand.

    The amount of people would keep getting lesser and lesser, so would it be the dependent variable, on the 'y' axis?

    ReplyDelete
  14. Lotta had a good hint for #5... I think you can see that there must have been 23 biscuits before any tricks started, yes?

    The number of tricks is the independent variable (horizontal or x-axis) and the number of biscuits is the dependent variable (vertical or y-axis).

    Then, you should be able to see that for each unit increase in the number of tricks (x), 3 biscuits are being awarded/eaten.

    Do you have an answer yet... let us know.

    Mr. C.

    ReplyDelete
  15. Hi Walter (first names only please!)

    I think you might be over-thinking #3, no equation or function is involved, just a graph.

    If the y-axis was the height and the x-axis was time, the line is simply going from the origin to the 7th floor, then the 9th floor, then the 10th and then back down to zero. The line moves from left to right as it does this because "time is marching on" as the elevator goes up and down. Each time the elevator stops, you would draw a small horizontal line segment... that would indicate that the elevator is stopped at a given floor.

    Ca-peesh?

    ReplyDelete
  16. Scroll up and see the elevator problem solution... make more sense now?

    ReplyDelete
  17. Oh I understand. Thanks Mr.C!
    So the line would go up to 7, have a small horizontal line, go up to 9, have a small horizontal line, and then go back down to 1?

    ReplyDelete
  18. Oh, and you are NOT graphing the number of people.... you are simply graphing THE HEIGHT OF THE ELEVATOR!!

    The independent variable is time (time is on your side as it marches on) and the dependent variable is the height of the elevator. The number of people is very very interesting, but you were not asked to graph that... be careful with what those darn story problems are asking you!!

    ReplyDelete
  19. Oh wow I didn't even notice the graph!
    Cool :D

    ReplyDelete
  20. Okay, thanks! :)
    This helped a lot, I will try to pick those word problems apart and see what to graph..

    independent variable is usually on the 'x' axis and dependent is on 'y' right?

    ReplyDelete
  21. independent variable ALWAYS usually on the HORIZONTAL axis (often labeled 'x') and dependent is ALWAYS on the VERTICAL axis (often labeled 'y').

    In the dog trick problem, the x-axis could be labeled 't' for tricks and the y-axis could be labeled 'b' for biscuits.

    So:

    b = -3t + 23

    or

    b = 23 - 3t

    yes?

    ReplyDelete